我有一些生成密文的PHP代码,如下所示:
<?php
$data = '12345678123456781234567812345678123456781234567812345678123456781234567812345678';
$ciphertext = mcrypt_encrypt('rijndael-128', 'M02cnQ51Ji97vwT4', $data, 'ecb');
echo base64_encode($ciphertext);
?>产生:
6tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Tq0nruhoXVfXZf8UThqEt06tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Q=我知道ECB不是用于这种类型数据的最佳模式,但我不是加密它的人。
我遇到的问题是node-crypto试图解密它。我的节点脚本如下:
var crypto = require("crypto");
var data = "6tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Tq0nruhoXVfXZf8UThqEt06tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Q=";
var out = '';
var decipher = crypto.createDecipher("aes-256-ecb", "M02cnQ51Ji97vwT4");
decipher.setAutoPadding(false); //this needs to be set otherwise i get an error:06065064:bad decrypt
out += decipher.update(data, "base64", "ascii");
out += decipher.final("ascii");
console.log(out);产生:
"3i<1pzV7A
vnE"3i<1pzV7A
vnE"3i<1pzV7A
vnE"3i<1pzV7A
vnE"3i<1pzV7A
vnE我不知道这里出了什么问题,原始数据的重复模式恢复了,但它是不正确的。我很难在openssl中找到等效的"rijndael-128“,似乎它必须是”aes-256- ECB“,并且不需要IV,因为它是ECB。如何让这两个库协同工作?
谢谢,J
发布于 2013-09-24 01:33:21
https://github.com/tugrul/node-mcrypt
var mcrypt = require('mcrypt');
var bfEcb = new mcrypt.MCrypt('rijndael-128', 'ecb');
bfEcb.open('M02cnQ51Ji97vwT4');
var ciphertext = new Buffer('6tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Tq0nruhoXVfXZf8UThqEt06tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Q=', 'base64');
var plaintext = bfEcb.decrypt(ciphertext);
console.log(plaintext.toString());发布于 2013-11-05 19:16:44
试试这个:
var crypto = require("crypto");
var data = "6tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Tq0nruhoXVfXZf8UThqEt06tJ67oaF1X12X/FE4ahLdOrSeu6GhdV9dl/xROGoS3Q=";
var out = '';
var decipher = crypto.createDecipheriv("aes-256-ecb", "M02cnQ51Ji97vwT4", '');
out += decipher.update(data, "base64");
out += decipher.final();
console.log(out);更改createDecipher(...)在我的例子中,使用第三个空参数(即所谓的初始化向量)执行createDecipheriv (注意末尾的iv )。在本例中,删除setAutoPadding(false)。
https://stackoverflow.com/questions/18176536
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