Fine-上传错误
Fine-上传错误
提问于 2013-07-23 16:56:55
因此，我尝试在我的网站中使用fine-uploader(最小jQuery演示)将一些图片上传到the服务器上传文件夹。然而，上传总是失败，我不知道为什么。
当我单击"upload a file“并选择一个文件时，它开始上传(进度条开始填充)，当它达到100%时，它会显示"Upload failed”，并在inspect元素中显示以下错误：
下面是upload.html：
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Fine Uploader - jQuery Wrapper Minimal Demo</title>
<link href="css/fineuploader-3.6.3.css" rel="stylesheet">
</head>
<body>
<div id="fine-uploader"></div>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script src="js/jquery.fineuploader-3.6.3.js"></script>
<script>
function createUploader() {
var uploader = new qq.FineUploader({
element: document.getElementById('fine-uploader'),
request: {
endpoint: 'upload_file.php'
}
});
}
window.onload = createUploader;
</script>
</body>
</html>和upload_file.php：
<?php
for($i=0; $i<count($_FILES['file']['type']); $i++) {
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"][$i]);
$extension = end($temp);
if ((($_FILES["file"]["type"][$i] == "image/gif")
|| ($_FILES["file"]["type"][$i] == "image/jpeg")
|| ($_FILES["file"]["type"][$i] == "image/jpg")
|| ($_FILES["file"]["type"][$i] == "image/pjpeg")
|| ($_FILES["file"]["type"][$i] == "image/x-png")
|| ($_FILES["file"]["type"][$i] == "image/png"))
&& ($_FILES["file"]["size"][$i] < 50000000)
&& in_array($extension, $allowedExts))
{
if ($_FILES["file"]["error"][$i] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"][$i] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"][$i] . "<br>";
echo "Type: " . $_FILES["file"]["type"][$i] . "<br>";
echo "Size: " . ($_FILES["file"]["size"][$i] / 1024) . " kB<br>";
echo "Temp file: " . $_FILES["file"]["tmp_name"][$i] . "<br>";
if (file_exists("upload\\" . $_FILES["file"]["name"][$i]))
{
echo $_FILES["file"]["name"][$i] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"][$i],
"\\upload\\" . $_FILES["file"]["name"][$i]);
echo "Stored in: " . "upload\\" . $_FILES["file"]["name"][$i];
}
}
}
else
{
echo "Invalid file";
}
}
?>回答 3
Stack Overflow用户
发布于 2013-07-27 03:04:36
您没有返回有效的JSON响应。要做到这一点，一个简单的方法是使用json_encode。
将当前的echo行放入一个数组中，并在使用json_encode之后回显该数组，以获得有效的JSON响应。
Stack Overflow用户
发布于 2013-08-01 05:34:28
<?php
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["qqfile"]["name"]);
$extension = end($temp);
/**
* This is just additional
*
*/
$folder = dirname( __FILE__) ."/testuploads";
if( !is_dir( $folder ))
{
@mkdir( $folder , 777 );
}
/**
* I remove the for loop since we are expecting a single file.
* The uploader supports multi uploads but what it exactly does is sending multiple request. See in the firebug.
* 1 request per file.
*/
if ((($_FILES["qqfile"]["type"] == "image/gif")
|| ($_FILES["qqfile"]["type"] == "image/jpeg")
|| ($_FILES["qqfile"]["type"] == "image/jpg")
|| ($_FILES["qqfile"]["type"] == "image/pjpeg")
|| ($_FILES["qqfile"]["type"] == "image/x-png")
|| ($_FILES["qqfile"]["type"] == "image/png"))
&& ($_FILES["qqfile"]["size"] < 50000000)
&& in_array($extension, $allowedExts))
{
if ($_FILES["qqfile"]["error"] > 0)
{
$msg['return_code'] = "Return Code: " . $_FILES["qqfile"]["error"] . "<br>";
}
else
{
/*
* I put the extra messages into array so we can display it later in json format.
*/
$msg['upload'] = "Upload: " . $_FILES["qqfile"]["name"] . "<br>";
$msg['type'] = "Type: " . $_FILES["qqfile"]["type"] . "<br>";
$msg['size'] = "Size: " . ($_FILES["qqfile"]["size"] / 1024) . " kB<br>";
$msg['temp_file'] = "Temp file: " . $_FILES["qqfile"]["tmp_name"] . "<br>";
if( $_FILES["qqfile"]["name"] <> "" )
if (file_exists($folder."/" . $_FILES["qqfile"]["name"]))
{
$msg['error_msg'] = $_FILES["qqfile"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["qqfile"]["tmp_name"],
$folder."/" . $_FILES["qqfile"]["name"]);
$msg['success_msg'] = "Stored in: " .$folder."/" . $_FILES["qqfile"]["name"];
/**
* Since we get here we have to tell your handler that the process is success
*/
$msg['success'] = "true";
}
}
}
else
{
$msg['error_msg'] = "Invalid file";
$msg['success'] = "false";
}
/**
* Display the result in json format.
*/
print json_encode( $msg );
?>第一件事是将它从循环中删除。尽管它支持多路上传，但每个文件只发送1个。请参见火虫中的。然后我使用文件夹的绝对路径，然后将响应转换为JSON格式。上面提供的代码有注释。
Stack Overflow用户
发布于 2013-08-01 10:19:58
尝试将您的权限设置为777
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原文链接：
https://stackoverflow.com/questions/17805676
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