
我的图看起来像上图。它是光通信网络的简化形式。每个顶点传递一种颜色。当两种颜色结合在一起("Mux")时,它就会产生新的颜色并发出新的光。在远端,颜色被分离并传递给相应的顶点。Mux、demux和transmit(“直通”)被捕获为edge。根据通风口图形成新的颜色。
如果我从一种颜色开始(例如“红色”),那么我必须只遍历有红色阴影(R1,R2)或红色阴影(D1,D2,P1)的边。
例如,如果我从R1开始,那么我可以遍历R1、D1、D2、P1、R2。它有另一个路径R1、D1、D2、P1、K1、R2,但它无效。因为K1没有红色阴影。
下面的查询运行得很好。我在遍历"mux“边缘时存储颜色。并使用此颜色来选择demux边缘。
g.V().hasLabel("R1").
repeat(choose(values("type")).
option("mux", aggregate(local, "colors").by("color").inV()).
option("demux", filter(values("color").as("c").
where("c", new P(new BitiseAndPredicate(), "colors")).
by().
by(unfold().limit(1))
).inV()).
option("stright", __.inV()).simplePath()).
until(hasLabel("R2")).
path().by(label()).toList();对于输入"R1“到"R2”,它工作得很好。R1、tx、D1、tx、D2、tx、P1、tx、R2
对于"Y1“到"Y2”,它返回empty。这是正确的,因为从G1到Y1没有边。
我想对查询进行更改。如果不能到达目的地,则打印到到达目的地为止,本例中为Y1、tx、D1、tx、D2、tx、G1
我使用emit()。但它会打印路径上的所有路径组合。
g.V().hasLabel("R1").
repeat(choose(values("type")).
option("mux", aggregate(local, "colors").by("color").inV()).
option("demux", filter(values("color").as("c").
where("c", new P(new BitiseAndPredicate(), "colors")).
by().
by(unfold().limit(1))
).inV()).
option("stright", __.inV()).simplePath()).
until(hasLabel("R2")).emit().
path().by(label()).toList();如果是简单的遍历,那么我可以使用emit(out().count().is(eq('0')))。但在这种情况下,最后一条边有更多的边,但它不符合我的"mux & demux“条件。我不能在“重复”步骤中重用相同的条件。实际的实现将更加复杂。
如果满足条件或重复步骤没有返回任何顶点,有没有办法发出路径。
以下是Java代码
import org.apache.tinkerpop.gremlin.process.traversal.P;
import org.apache.tinkerpop.gremlin.process.traversal.Path;
import org.apache.tinkerpop.gremlin.process.traversal.dsl.graph.GraphTraversal;
import org.apache.tinkerpop.gremlin.process.traversal.dsl.graph.GraphTraversalSource;
import org.apache.tinkerpop.gremlin.process.traversal.dsl.graph.__;
import org.apache.tinkerpop.gremlin.structure.Vertex;
import org.apache.tinkerpop.gremlin.util.function.Lambda;
import org.janusgraph.core.*;
import org.janusgraph.core.schema.JanusGraphManagement;
import java.util.ArrayList;
import java.util.List;
import static org.apache.tinkerpop.gremlin.process.traversal.P.eq;
import static org.apache.tinkerpop.gremlin.process.traversal.P.without;
import static org.apache.tinkerpop.gremlin.process.traversal.Scope.local;
import static org.apache.tinkerpop.gremlin.process.traversal.dsl.graph.__.*;
import static org.janusgraph.core.Multiplicity.MULTI;
public class ColourTraversal
{
public static void main( String[] args )
{
//External db
GraphTraversalSource g =null;
//inmemory db
JanusGraph graph = JanusGraphFactory.build().set("storage.backend", "inmemory").open();
g = graph.traversal();
try
{
populateData(g);
g.tx().commit();
printPath(g, "R1", "R2");
System.out.println();
printPath(g, "Y1", "Y2");
g.close();
} catch (Exception e)
{
e.printStackTrace();
}
}
private static void printPath(GraphTraversalSource g, String start, String end)
{
List<Path> pathList = g.V().hasLabel(start).
repeat(repeatStep().simplePath()).
emit(hasLabel(end)).
path().by(label()).toList();
for (Path path : pathList)
{
for (int i = 0; i < path.size(); i++)
{
String label = path.get(i);
System.out.println(label);
}
}
}
private static GraphTraversal<?, Vertex> repeatStep()
{
GraphTraversal<?, ?> repeatStepTrav =
outE("tx").choose(values("type")).
option("mux", aggregate(local, "colors").by("color").inV()).
option("demux", filter(values("color").as("c").
where("c", new P(new BitiseAndPredicate(), "colors")).
by().
by(unfold().limit(1))
).inV()).
option("stright", __.inV());
return (GraphTraversal<Vertex, Vertex>) repeatStepTrav;
}
private static void populateData(GraphTraversalSource g)
{
Vertex r1 = g.addV("R1").next();
Vertex r2 = g.addV("R2").next();
Vertex d1 = g.addV("D1").next();
Vertex d2 = g.addV("D2").next();
Vertex g1 = g.addV("G1").next();
Vertex b1 = g.addV("B1").next();
Vertex b2 = g.addV("B2").next();
Vertex b3 = g.addV("B3").next();
Vertex y1 = g.addV("Y1").next();
Vertex p1 = g.addV("P1").next();
addEdge(g, r1, d1, "mux", 4);
addEdge(g, y1, d1, "mux", 2);
addEdge(g, b1, d1, "mux", 1);
addEdge(g, d1, d2, "stright", 7);
addEdge(g, g1, d2, "mux", 3);
addEdge(g, p1, d2, "mux", 5);
addEdge(g, b2, g1, "mux", 1);
addEdge(g, b3,p1, "mux", 1);
addEdge(g, r2,p1, "mux", 4);
addEdge(g, d1, r1, "demux", 4);
addEdge(g, d1, y1, "demux", 2);
addEdge(g, d1, b1, "demux", 1);
addEdge(g, d2, d1, "stright", 7);
addEdge(g, d2,g1, "demux", 3);
addEdge(g, d2,p1, "demux", 5);
addEdge(g, g1,b2, "demux", 1);
addEdge(g, p1,b3, "demux", 1);
addEdge(g, p1,r2, "demux", 4);
Vertex k1 = g.addV("K1").next();
addEdge(g, p1, k1, "demux", 0);
addEdge(g, k1, r2, "demux", 0);
addEdge(g, k1, p1, "mux", 0);
addEdge(g, r2, k1, "mux", 0);
// Vertex y2 = g.addV("Y2").next();
// addEdge(g, y2, g1, "mux", 2);
// addEdge(g, g1,y2, "demux", 2);
}
private static void addEdge(GraphTraversalSource g, Vertex source, Vertex destination,String type,int color) {
GraphTraversal t = g.V(source).addE("tx").to(destination).property("type", type).property("color", color);
t.next();
}
}
import java.util.function.BiPredicate;
public class BitisetAndPredicate implements BiPredicate {
@Override
public boolean test(Object o, Object o2) {
int left = (int) o;
int right = (int) o2;
return (left & right) == right;
}
}发布于 2021-08-05 07:59:31
除了使用emit()步骤之外,您还可以向until()步骤添加析取条件,以测试没有更多外边的路径。
下面的gremlin控制台中的会话使用了tinkerpop modern示例图形,展示了如何:
graph = TinkerFactory.createModern()
g = graph.traversal()
// Your old query
gremlin> g.V(1).repeat(out()).until(has("name", "ripple")).path()
==>[v[1],v[4],v[5]]
// A query with additional condition to stop the repeat
gremlin> g.V(1).repeat(out()).until(or(has("name", "ripple"), out().count().is(eq(0)))).path()
==>[v[1],v[3]]
==>[v[1],v[2]]
==>[v[1],v[4],v[5]]
==>[v[1],v[4],v[3]]https://stackoverflow.com/questions/68558169
复制相似问题