使用Python64位win32com (Solidworks-API)时出现异常:异常SldWorks.Application.InvokeTypes

Question

我的Windows Server2003标准x64版有64位的Python2.7 ( Python -2.7.3.amd64.msi)和64位的win32扩展(pywin32-218.win-amd64-py2.7.exe)。我的应用程序是SolidWorks 2012 x64版。然后我用

C:\Python27\Lib\site-packages\win32com\client\makepy.py "D:\Program Files\SolidWorks Corp\SolidWorks\sldworks.tlb" the file 83A33D31-27C5-11CE-BFD4-00400513BB57x0x20x0.py 

并使用

C:\Python27\Lib\site-packages\win32com\client\makepy.py "D:\Program Files\SolidWorks Corp\SolidWorks\swconst.tlb" the file 4687F359-55D0-4CD3-B6CF-2EB42C11F989x0x20x0.py

我的以下代码在带有32位Python2.4和32位Win32扩展的32位Windowes XP上运行良好。但是在我的64位服务器上，我通过调用ExitApp()-method得到了一个异常"SldWorks.Application.InvokeTypes“。原因是什么?我如何解决这个问题？谢谢你的提示，托马斯

 try:

        pythoncom.CoInitializeEx(pythoncom.COINIT_APARTMENTTHREADED)

        sldworks = gencache.EnsureModule('{83A33D31-27C5-11CE-BFD4-00400513BB57}', 0x0, 20, 0) 
        print "sldworks = " + str(sldworks)       
        swconst = gencache.EnsureModule('{4687F359-55D0-4CD3-B6CF-2EB42C11F989}', 0x0, 20, 0) 
        print "swconst = " + str(swconst)   


        sw = sldworks.ISldWorks(DispatchEx('SldWorks.Application'))  
        print "sw = " + str(sw)   

        sw.ExitApp() 

    except Exception, value:        
        print "Exception occured, value = ", value 

下面是打印结果：

sldworks = module 'win32com.gen_py.83A33D31-27C5-11CE-BFD4-00400513BB57x0x20x0' from 'C:\Python27\lib\site-packages\win32com\gen_py\83A33D31-27C5-11CE-BFD4-00400513BB57x0x20x0.pyc'  

swconst = module 'win32com.gen_py.4687F359-55D0-4CD3-B6CF-2EB42C11F989x0x20x0' from 'C:\Python27\lib\site-packages\win32com\gen_py\4687F359-55D0-4CD3-B6CF-2EB42C11F989x0x20x0.pyc'        

sw = win32com.gen_py.SldWorks 2012 Type Library.ISldWorks instance at 0x82548360  

Exception occured, value = SldWorks.Application.InvokeTypes 

Answer 1

使用

sw = win32com.client.Dispatch("SldWorks.Application")

相反，

sw = sldworks.ISldWorks(DispatchEx('SldWorks.Application'))

与Python2.432位和win32扩展32位，它的工作很好。

托马斯

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