我试图从从文本文档中提取的模式中提取ngram,这些模式具有不同数量的术语。
例如:如果模式p={t1,t2,t3}
我们需要提取ngram 3
应该是这样的
t1
t2
t3
t1, t2
t2,t3
t1,t2,t3我写了一些代码,但不能很好地工作。
public Hashtable<String, Pattern> findGrams(XMLDocument d) {
ArrayList<Pattern> patterns = d.getPatterns();
System.out.println("patterns " + d.getPatterns());
ArrayList terms = new ArrayList();
Hashtable Grams = new Hashtable();
String s = "";
// to extract all terms from the pattern
for (int i = 0; i < patterns.size(); i++) {
Pattern pat = (Pattern) patterns.get(i);
terms.clear();
for (int z = 0; z < pat.getNumitems(); z++) {
terms.add(pat.getItems().get(z).toString());
}
// to generate grams from the pattern
int j = 0;
int x=0;
for (int y = 1; y <= ngram ; y++) {
for ( x = 0; x < terms.size() & j != y; x++) {
s = terms.get(x).toString();
if (y > 1) {
for (j = x + 1; j < terms.size() & terms.indexOf(j) < ngram; j++) {
s = s + "," + terms.get(j).toString();
}
}
if (!Grams.contains(s)) {
System.out.println(s);
Grams.put(s, i);
}
}
}
}
return (Grams);
}有什么需要帮忙的吗,
发布于 2012-09-23 17:51:20
我希望这能给你想要的东西。
import java.util.*;
public class Test {
public static List<String> ngrams(int n, String str) {
List<String> ngrams = new ArrayList<String>();
String[] words = str.split(" ");
for (int i = 0; i < words.length - n + 1; i++)
ngrams.add(concat(words, i, i+n));
return ngrams;
}
public static String concat(String[] words, int start, int end) {
StringBuilder sb = new StringBuilder();
for (int i = start; i < end; i++)
sb.append((i > start ? " " : "") + words[i]);
return sb.toString();
}
public static void main(String[] args) {
for (int n = 1; n <= 3; n++) {
for (String ngram : ngrams(n, "t1 t2 t3"))
System.out.println(ngram);
System.out.println();
}
}
}https://stackoverflow.com/questions/11452290
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