Spring Data findBy枚举

Question

我遇到过这样的问题，不知道该如何解决。问题是下一个:我有下一个模型：

@Entity(name="Authority")
@Table(name="AUTHORITIES")
public class Authority implements GrantedAuthority {

@Id
private long id;

@Enumerated(EnumType.STRING)
@Column(name="authority")
private asdevelopment.action.enums.Authority authority;

/**
 * 
 */
private static final long serialVersionUID = 1L;

@Override
public String getAuthority() {
    return authority.toString();
}

/**
 * @return the id
 */
public long getId() {
    return id;
}

}


public enum Authority {

CLIENT_ROLE, ADMIN_ROLE;

}

我可以节省权限和获得ID没有任何问题。但是当我在存储库中调用next方法时：

domain.Authority findByAuthority(enums.Authority authority);

我得到了下一个异常：

Hibernate: select top ? authority0_.id as id1_, authority0_.authority as authority1_ from AUTHORITIES authority0_ where authority0_.authority=?
13:48:01.125  WARN [main] org.hibernate.engine.jdbc.spi.SqlExceptionHelper:143 - SQL   Error: 1064, SQLState: 42000
13:48:01.125 ERROR [main] org.hibernate.engine.jdbc.spi.SqlExceptionHelper:144 - You    have an error in your SQL syntax; check the manual that corresponds to your MySQL server    version for the right syntax to use near '2 authority0_.id as id1_, authority0_.authority as authority1_ from AUTHORITIES ' at line 1

Answer 1

对于MySQL，select top ? ...肯定不是有效的查询。

在您的Hibernate配置中检查SQL dialect setting。