MessageBroker.getMessageBroker( null )获取null指针异常

Question

我正在创建动态目的地

MessageBroker broker = MessageBroker.getMessageBroker(null)；

        MessageService service = (MessageService) broker.getService("message-service");
        MessageDestination destination = (MessageDestination) service.createDestination("Group1");

        if (service.isStarted()) {
            destination.start();
        }

但是我得到了空指针异常MessageBroker broker =MessageBroker.getMessageBroker(空)；

有人能帮我吗？

Answer 1

您可能正在使用Spring blazeds集成。Flex默认使用"__default__"作为messageBroker id，在这种情况下，您的MessageBroker.getMessageBroker(null)保持为真。但是，Spring使用"_messageBroker"作为代理id。因此，您可能需要使用

MessageBroker broker=MessageBroker.getMessageBroker("_messageBroker");

这个URL说得更好……

http://forum.springsource.org/showthread.php?t=72964

MessageBroker broker=MessageBroker.getMessageBroker(BeanIds.MESSAGE_BROKER);