我有一个取消按钮,用来刷新数值。现在,我已经将它们转换为刷新或重新加载页面,并移动到只读页面。所以改变了取消按钮来调用这样的函数,
function chkArea(){
var url='<c:out value="${model.contextPath}"/>/abcHandler.do?operation=view;
document.forms[0].action=url;
document.forms[0].submit();
}现在,当我提交cancel时,我在UI中得到以下消息,
java.lang.IllegalStateException: Response has already been committed at com.evermind[Oracle Containers for J2EE 10g (10.1.3.4.0) ].server.http.EvermindHttpServletResponse.resetBuffer(EvermindHttpServletResponse.java:1892) at com.evermind[Oracle Containers for J2EE 10g (10.1.3.4.0) ].server.http.ServletRequestDispatcher.unprivileged_forward(ServletRequestDispatcher.java:249) at com.evermind[Oracle Containers for J2EE 10g (10.1.3.4.0) ].server.http.ServletRequestDispatcher.access$100(ServletRequestDispatcher.java:51) at com.evermind[Oracle Containers for J2EE 10g (10.1.3.4.0) ].server.http.ServletRequestDispatcher$2.oc4jRun(ServletRequestDispatcher.java:193) at oracle.oc4j.security.OC4JSecurity.doPrivileged(OC4JSecurity.java:284)........控制台显示以下错误:
javax.servlet.ServletException: The "url" attribute illegally evaluated to "null" or "" in <import>
at com.evermind.server.http.EvermindPageContext.handlePageThrowable(EvermindPageContext.java:899)
at com.evermind.server.http.EvermindPageContext.handlePageException(EvermindPageContext.java:816)我在JS或JSP中看不到任何错误。似乎出了什么问题?有什么建议吗?
发布于 2013-06-25 11:05:26
当您在jsp的输出流上写入内容,然后再次对其执行某些操作时,就会出现此错误。这会导致IllegalStateException。当响应已经提交时,您不应该执行任何操作。所谓提交,我的意思是将响应发送回客户端。一个常见的场景是
OutputStream stream = response.getOutPutStream();
stream.write("something here");
stream.flush();
RequestDispatcher rd = request.getRequestDispatcher("someFile.jsp");
rd.forward(request, response); // You can't do this because stream is already writtenhttps://stackoverflow.com/questions/17288481
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