我有一个脚本,它接受太旧的路径名/文件(通过用户输入决定)并删除它们。我想单独列出每个目录,并要求确认删除每个目录中的旧文件。
因此,我有一个数组(@oldDir),它包含多个数组(每个目录),这些数组包含字符串(完整路径名)。
@oldDirs = (@AirDefense,@Arcsight,@Avocent,@BlueCoat,@Checkpoint,@Cisco,@Crossbeam,@FireE ye,@lostAndFound,@rancid,@Riverbed,@Symantec,@Wiki,@WLAN)
if($oldPathsSize != 0)
{
my $dirNamesCounter = 0;
my @dirNames = ('/AirDefense','/Arcsight','/Avocent','/BlueCoat','/Checkpoint','/Cisco','Crossbeam','FireE ye','/lost+found','/rancid-2.3.8','/Riverbed','/Symantec','/Wiki','/WLAN');
foreach my @direc (@oldDirs)
{
my $size = @direc;
print "Confirm Deletion of $size Old files in $dirNames[$dirNamesC]: \n";
$dirNamesCounter++;
foreach my $pathname (@direc)
{
print "\t$pathname\n";
}
print "\nDelete All?(y/n): ";
my $delete = <STDIN>;
chomp($delete);
if($delete eq "y")
{
#delete file
}
}
}我的问题是关于第一个foreach语句。两者都是数组,@direc是不允许的,因为我需要在foreach...but的那一部分有一个标量值,它们都是数组!如果可能的话,我该怎么做呢?
发布于 2013-06-06 04:22:01
你应该读一下perllol - Manipulating Arrays of Arrays in Perl。您不能像这样创建多维数组:
my @array1 = (1, 2, 3);
my @array2 = qw/a b c/;
my @multi = (@array1, @array2);取而代之的是,数组将被展平,并且@multi将包含
1, 2, 3, 'a', 'b', 'c'你必须使用引用:
my @multi = (\@array1, \@array2);
for my $ref (@multi) {
for my $inner (@$ref) {
# ...
}
}https://stackoverflow.com/questions/16949013
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