软件电容器

Question

我需要使用一个软件电容器。

我有一个有n个样本的信号。我需要过滤它。

是否有包含软件电容器和其他电气元件的c++库(或单个函数)？

Answer 1

如果你想要的是一个非常简单的函数来对样本数组应用自定义过滤器，那么这应该可以做到……只需用更像正确的方程式的东西替换电容器()函数中循环中的逻辑即可。

#include <stdio.h>
#include <math.h>

#define INRADS *3.1416/180.0

#define NUM_SAMPLES 1000

double capVoltage = 0;
//this is a simple (capacitor like) filter.
int capacitor(double* sample, long samples, double capacitorValue, double totalTime, double initialCapVoltage){

    capVoltage = initialCapVoltage;

    for (int i = 0; i<= samples-1; i++){ //loop through all the samples
        if (sample[i] > capVoltage){ //charge the cap
            //put your math in here, calculate voltages based on capacitorValue, totalTime and capVoltage
            //this next line is just for testing purposes
            capVoltage += 0.2;
        }
        if (sample[i] < capVoltage){ //discharge the cap
            //put your math in here, calculate voltages based on capacitorValue, totalTime and capVoltage
            //this next line is just for testing purposes
            capVoltage -= 0.2;
        }
        sample[i] = capVoltage;
        printf("Changed sample %d to %f \n", i, sample[i]);
    }

}

double* myVoltageSamples; //generic wave sample
double* myVoltageSamples2; //generic wave sample

int main(){

    myVoltageSamples = new double[NUM_SAMPLES]; //let's say this is 1 sample every millisecond for one second
    myVoltageSamples2 = new double[NUM_SAMPLES]; //let's say this is 1 sample every millisecond for one second

    for (int i = 0; i<= NUM_SAMPLES-1; i++){ //put some data in the sample array
        myVoltageSamples[i] = sin( ( i ) INRADS );      // a simple, generic sin wave
        myVoltageSamples2[i] = myVoltageSamples[i];
        printf("Adding %f to the sample.\n", myVoltageSamples[i]);
    }
    //we now have a generic signal

    //apply your basic (capacitor) filter
    capacitor(myVoltageSamples2, NUM_SAMPLES, 0.001, 1000, 0); //1mF cap, one second, start voltage = 0

    //compare the start and finish:
    printf("first signal:\n");
    for (int i = 0; i<= NUM_SAMPLES-1; i++){ //put some data in the sample array
        for (int j = 0; j<=((int)(myVoltageSamples[i]*20))+20-1; j++){
            printf(".");
        }
        printf("X\n");
    }

    printf("second signal:\n");
    for (int i = 0; i<= NUM_SAMPLES-1; i++){ //put some data in the sample array
        for (int j = 0; j<=((int)(myVoltageSamples2[i]*20))+20-1; j++){
            printf(".");
        }
        printf("X\n");
    }

    delete myVoltageSamples;
    delete myVoltageSamples2;

}