python minidom xml解析

Question

我正在尝试找到一种在使用minidom解析xml文件时获取索引号的方法。xml将如下所示

<stuff>
    <morestuff>
        <sometag>catagory1</sometag>
        <path pathversion="1">/path Im looking to for</path> #<--info i'm after
        <path pathversion="2">/path I don't need</path>
        <path pathversion="3">/path I don't need</path>
    </morestuff>
    <morestuff>
        <sometag>catagory2</sometag>
        <path pathversion="1">/other path I'm looking for</path> #<--info i'm after
        <path pathversion="2">/path I don't need</path>
        <path pathversion="3">/path I don't need</path>
    </morestuff>
</stuff>

我想做这样的事情

for element in node.getElementsByTagName('sometag'):
    if element.firstChild.data == 'catagory1':
        elementid = element.indexnumber #<----how do I write the [0], or [1] to a variable so I can use it to discribe the position in the next line
        var1 = node.getElementsByTagName('path')[elementid].firstChild.data
    if element.firstChild.data == 'catagory2':
        elementid = element.indexnumber
        var2 = node.getElementsByTagName('path')[elementid].firstChild.data

Answer 1

这将创建一个包含所需信息的字典：

import xml.dom.minidom
doc = xml.dom.minidom.parseString(test)

paths = {}

for element in doc.getElementsByTagName('morestuff'):
    # get the text value of the sometag tag
    category = element.getElementsByTagName('sometag')[0].firstChild.nodeValue

    # get all the paths which are children of the morestuff element
    for path in element.getElementsByTagName('path'):
        if path.getAttribute('pathversion') == '1':
            pathstr = path.firstChild.nodeValue
            paths[category] = pathstr

print paths

我得到的输出是：

{u'catagory1': u'/path Im looking to for', u'catagory2': u"/other path I'm looking for"}

Answer 2

使用Keith建议的etree如何：

['/path Im looking to for', "/other path I'm looking for"]

使用以下代码：

import xml.etree.ElementTree as ET
tree = ET.fromstring('''<stuff>
    <morestuff>
        <sometag>catagory1</sometag>
        <path pathversion="1">/path Im looking to for</path>
        <path pathversion="2">/path I don't need</path>
        <path pathversion="3">/path I don't need</path>
    </morestuff>
    <morestuff>
        <sometag>catagory2</sometag>
        <path pathversion="1">/other path I'm looking for</path>
        <path pathversion="2">/path I don't need</path>
        <path pathversion="3">/path I don't need</path>
    </morestuff>
</stuff>
''')
print [e.text for e in tree.findall('.//morestuff/path[@pathversion="1"]')]