我刚开始使用Django TastyPie来公开数据。尝试使用urls.py的tastypie.Api将资源捆绑在一起
http://django-tastypie.readthedocs.org/en/latest/tutorial.html#creating-resources中给出的示例不能开箱即用。
我的urls.py条目:
#now for the api
from tserver.api import PurchaseResource,DataResource
#combine several APIs
from tastypie.api import Api
api = Api(api_name='')
api.register(PurchaseResource(),canonical=True)
api.register(DataResource(),canonical=True)
urlpatterns = patterns('', (r'^api/',include(api.urls)),
)和api.py
#!/bin/env python
from tastypie.resources import ModelResource
from tastypie import fields
from tserver.models import Purchase,Data
class DataResource(ModelResource):
class Meta:
queryset = Data.objects.all()
class PurchaseResource(ModelResource):
Info = fields.ForeignKey(DataResource,'data')
class Meta:
queryset = Purchase.objects.all()
resource_name = 'purchase'和models.py
class Data(models.Model):
tagID = models.CharField(max_length=40)
dtime = models.DateTimeField()
vcardf = models.CharField(max_length = 600)
class Purchase(models.Model):
Info = models.ForeignKey('Data',unique=True)
payment_method = models.CharField(max_length=20,choices=PAYMENT_METHOD)
TotalAmount = models.DecimalField(max_digits = 20, decimal_places=2)
TotalDiscount = models.DecimalField(max_digits = 20, decimal_places=2)
valid_upto = models.DateTimeField()最后,当我尝试它的时候,错误:
http://localhost:8000/api/data/1/?format=json 结果如下:
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/api/data/1/?format=json
Using the URLconf Django tried these URL patterns, in this order:
^admin/
^(?P<api_name>)/$ [name='api__top_level']
^(?P<api_name>)/
^(?P<api_name>)/
The current URL, api/data/1/, didn't match any of these.但是如果我只在urls.py中使用,这个问题就不存在了
urlpatterns = patterns('', (r'^api/',include(DataResoure().urls)),
)当我们尝试使用api.register(...)将事物联系在一起时,这里的问题是什么?
发布于 2011-12-30 05:17:56
我们总是指定api_name和资源名称。喜欢
注册文件
public_api = Api(api_name='public')
public_api.register(BookingPostResource())
public_api.register(SearchResource())
private_api = Api(api_name='private')
private_api.register(BookingPostResource())
private_api.register(SearchResource())urls.py
urlpatterns = patterns('',
url(r'^api/', include(public_api.urls)),
url(r'^api/', include(private_api.urls)),
)然后我们得到url:
http://www.mysite.com/api/public/{resource_name}
http://www.mysite.com/api/private/{resource_name}
我想警告你,tastypie表现出非常糟糕的生产力,并且包含一些严重的问题,这可能会导致数据丢失,在它开始正常工作之前,我们做了很多补丁。目前我们正在转向我们自己的框架。我强烈建议你使用更小的东西,如活塞,但它也不是银弹。
https://stackoverflow.com/questions/8666058
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