如何阻止Py_Initialise使应用程序崩溃？

Question

在VBA和VB6中，我调用了一个动态链接库来创建一个Python解释器。如果将PATH环境变量设置为指向"C:\python27"，将PYTHONPATH设置为"c:\python27\lib"，则一切正常。

如果我没有设置PATH，那么调用Py_Initialise()会导致XL或我的VB6应用程序崩溃，即使我先用"c:\python27\python27.exe"调用Py_SetProgramName。

我想在VB/VBA中指定安装，而不是在环境中设置，因为我不能在XL中这样做(适用于VB6)。

Answer 1

到目前为止，我找到的最好的答案是，这是Python - http://bugs.python.org/issue6498中的一个bug。解释器似乎在某些错误时调用exit()，而不是将代码传回调用者。如果你在一个应用程序中嵌入python，那就不太友好了。但这就对了。

Answer 2

在调用dll之前尝试更改工作目录：

在您的VBA代码中：

chdir("c:\python27\") '- change the working-directory for python
=> call dll '- call the dll
chdir(app.Path) '- change back to your folder (maybe you want to save your current folder bevore you change it the first time and change back to this?!)

致敬托马斯

Answer 3

您可以简单地检查是否设置了所需的环境变量：

dim PPath as string
PPath = trim(Environ("PYTHONPATH"))
if (PPath<>"")
  <call dll>
else
  msgbox ("Error!")
end if

或者你可以在另一个测试进程中运行dll :如果这个调用工作，你知道调用dll是可以的-它取决于你使用的DLL调用，所以我不确定这一点：

Private Declare Function CloseHandle Lib "kernel32" (ByVal _
    hObject As Long) As Long

Private Declare Function OpenProcess Lib "kernel32" (ByVal _
    dwDesiredAccess As Long, ByVal bInheritHandle As _
    Long, ByVal dwProcessId As Long) As Long

Private Declare Function GetExitCodeProcess Lib "kernel32" _
    (ByVal hProcess As Long, lpExitCode As Long) As Long

Const STILL_ACTIVE = &H103
Const PROCESS_ALL_ACCESS = &H1F0FFF

...
dim IsActive as boolean
dim Handle as long
Dim TaskID As Long
TaskID = Shell("rundll32.exe pyton.dll Py_Initialise()", vbNormalNoFocus)

<wait for some time>

'- check if pyton.dll is still running
Handle = OpenProcess(PROCESS_ALL_ACCESS, False, TaskID)
Call GetExitCodeProcess(Handle, ExitCode)
Call CloseHandle(Handle)

IsActive = IIf(ExitCode = STILL_ACTIVE, True, False)

if (not IsActive) then
  msgbox ("Error!")
else
  <kill process>
  <call dll normally>
end if

致敬托马斯