无法分析NSAppleScript方法executeAndReturnError返回的结果

Question

这是我使用的代码：

NSDictionary *errorInfo=nil;
NSString *source=@"tell application \"Mail\"\nget name of mailbox of every account\nend tell";
NSAppleScript *run = [[NSAppleScript alloc] initWithSource:source];
NSAppleEventDescriptor *aDescriptor=[[NSAppleEventDescriptor alloc]init];
aDescriptor=[run executeAndReturnError:&errorInfo];
[aDescriptor coerceToDescriptorType:'utxt'];
NSLog(@"result:%@",[aDescriptor stringValue]);

我得到的输出: result:(null)

请提前在this.Thanks上帮助我：)

Answer 1

IIRC，它将返回一个用列表描述符填充的列表描述符。你需要遍历它们并提取出你想要的信息。您还初始化了一个描述符，然后立即覆盖了它的指针。做一些类似的事情(未测试)：

NSDictionary *errorInfo = nil;
NSString *source = @"tell application \"Mail\"\nget name of mailbox of every account\nend tell";
NSAppleScript *run = [[NSAppleScript alloc] initWithSource:source];
NSAppleEventDescriptor *aDescriptor = [run executeAndReturnError:&errorInfo];
NSInteger num = [aDescriptor numberOfItems];

// Apple event descriptor list indexes are one-based!
for (NSInteger idx = 1; idx <= num; ++idx) {
    NSAppleEventDescriptor *innerListDescriptor = [aDescriptor descriptorAtIndex:idx];

    NSInteger innerNum = [innerListDescriptor numberOfItems];

    for (NSInteger innerIdx = 1; innerIdx <= innerNum; ++innerIdx) {
        NSString *str = [[innerListDescriptor descriptorAtIndex:innerIdx] stringValue];
        // Do something with str here
    }
}