我使用以下代码将一些数据写入SequenceFile格式的文件。当程序运行一段时间时,我通过eclipse控制台上的红色按钮中断程序。但是,当我检查hdfs上的数据文件时,序列文件的大小为零。而且也不能使用'hadoop fs -text filename‘命令查看文件。当我使用SequenceFile.Reader读取之前创建的文件时,我遇到了“exception in thread "main”java.io.EOFException“异常。在这种情况下,该怎么办呢?我的开发环境是eclipse3.7(在CentOS 7上)和hadoop集群(hadoop version 1.0.3 )在windows6上。
类序列扩展了Thread {
private String uri = "hdfs://172.20.11.60:9000";
private String filePath = "/user/hadoop/input/";
private String fileName = "Sequence-01.seq";
public SequenceFile.Writer writer;
private static int cnt = 0;
private void init() {
Configuration conf = new Configuration();
try {
FileSystem fs = FileSystem.get(URI.create(uri), conf);
writer = SequenceFile.createWriter(fs, conf, new Path(filePath
+ fileName), LongWritable.class, Text.class);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public Sequence() {
init();
}
@Override
public void run(){
while(true){
try {
writer.append(new LongWritable(100), new Text("hello,world"));
cnt++;
if(cnt%100 == 0){
System.out.println("flush current data to file system");
writer.syncFs();
}
} catch (IOException e) {
// TODO Auto-generated catch block
System.out.println("append data error");
e.printStackTrace();
}
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
System.out.println("thread interupted");
e.printStackTrace();
}
}
}}
公共类TestSequenceFile {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
new Sequence().start();
}}
发布于 2013-03-21 15:55:05
一般的建议是:不要打断这个过程。
解决方案:对我来说,以下代码运行得很好。
import java.io.IOException;
import java.net.URI;
import org.apache.hadoop.conf.Configuration;
import org.apache.hadoop.fs.FileSystem;
import org.apache.hadoop.fs.Path;
import org.apache.hadoop.io.IOUtils;
import org.apache.hadoop.io.IntWritable;
import org.apache.hadoop.io.SequenceFile;
import org.apache.hadoop.io.Text;
public class SequenceFileWriteDemo {
private static final String[] DATA = {
"One, two, buckle my shoe",
"Three, four, shut the door",
"Five, six, pick up sticks",
"Seven, eight, lay them straight",
"Nine, ten, a big fat hen"};
public static void main(String[] args) throws IOException {
//String uri = "/home/Desktop/inputSort.txt";
String uri = "hdfs://localhost:9900/out1.seq";
Configuration conf = new Configuration();
FileSystem fs = FileSystem.get(URI.create(uri), conf);
Path path = new Path(uri);
IntWritable key = new IntWritable();
Text value = new Text();
SequenceFile.Writer writer = null;
try {
writer = SequenceFile.createWriter(fs, conf, path,
key.getClass(), value.getClass());
for (int i = 0; i < 130; i++) {
key.set(100 - i);
value.set(DATA[i % DATA.length]);
System.out.printf("[%s]\t%s\t%s\n", writer.getLength(), key, value, key.getClass(), value.getClass());
writer.append(key, value);
}
} finally {
IOUtils.closeStream(writer);
}
}}有关写入序列文件的详细信息,请参阅Hadoop一书--权威指南(O‘’Reilly出版物)。
发布于 2014-01-31 14:34:28
是的,Hadoop权威指南最适合它,这里是读取和写入序列文件的示例。
实际上,序列文件形成了字节序列或hadoop Writables,主要用于组合各种小文件,以组合并馈送到map函数。
http://javatute.com/javatute/faces/post/hadoop/2014/creating-sequence-file-using-hadoop.xhtml
https://stackoverflow.com/questions/15541678
复制相似问题