所以如果我运行:
ffmpeg -t 10 -re -i "rtmp://170.93.143.150/rtplive/ app=rtplive/ playpath=e000990f025f0075004d823633235daa swfUrl=http://www.chart.state.md.us/video/mediaplayer/player.swf pageUrl=http://www.chart.state.md.us/video/video.asp?feed=e000990f025f0075004d823633235daa stop=5000 flashver=`LNX 11,2,202,262` live=true" test.flv -report它为我提供了5秒的视频快照,这些视频来自put流,并被放到test.flv中。现在,我想在java中使用xuggle做同样的事情,只是每次我尝试打开容器时,它都会出错,并将x设置为-1:
public IMediaReader grabStream(IMediaReader reader) throws IOException
{
String rtmp = "rtmp://170.93.143.150/rtplive/";
rtmp = rtmp + " app=rtplive/";
rtmp = rtmp + " playpath=e000990f025f0075004d823633235daa";
rtmp = rtmp + " swfUrl=http://www.chart.state.md.us/video/mediaplayer/player.swf";
rtmp = rtmp + " pageUrl=http://www.chart.state.md.us/video/video.asp?feed=e000990f025f0075004d823633235daa";
rtmp = rtmp + " flashver=`LNX 11,2,202,262`";
rtmp = rtmp + " live=true";
IContainer container = IContainer.make();
IMediaReader newReader = ToolFactory.makeReader(container);
int x = container.open(rtmp, IContainer.Type.READ, null, true, false);
if (x < 0)
{
IError ie = IError.make(x);
System.out.println("Open error: " + ie.getType().toString());
throw new RuntimeException("failed to open with error" + x);
}
return newReader;
}也许最好的方法是以某种方式使用inputstream将ffmpeg流传输到xuggle容器中?或者也许有另一种方法可以将webstream中的流传输到java?
发布于 2013-02-26 01:44:27
rtmp源字符串的格式如下
String rtmpSourceUrl = "rtmp://hostname/appName/streamName"; 然后,我建议创建阅读器,如下所示
IContainerFormat inFormat = IContainerFormat.make();
inFormat.setInputFormat("flv"); // set the input format to avoid FFMPEG
// probing
IMediaReader reader = ToolFactory.makeReader(rtmpSourceUrl);
reader.setQueryMetaData(false);
reader.setBufferedImageTypeToGenerate(-1);
reader.getContainer().setForcedVideoCodec(ID.CODEC_ID_FLV1);
reader.getContainer().open(rtmpSourceUrl , IContainer.Type.READ, inFormat,
true, false);这解决了你的问题吗?
https://stackoverflow.com/questions/14879121
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