在Ruby中做XMLHttpRequest的最简单的方法？

Question

我想用Ruby语言写一篇XMLHttpRequest文章。我不想使用像Watir这样的框架。像Mechanize或Scrubyt这样的就可以了。我该怎么做呢？

Answer 1

机械化：

require 'mechanize'
agent = Mechanize.new
agent.post 'http://www.example.com/', :foo => 'bar'

Answer 2

使用'net/http‘的示例，(ruby 1.9.3)：

你只需要在你的POST请求中为XMLHttpRequest添加一个额外的头(见下文)。

require 'net/http'
require 'uri'  # convenient for using parts of an URI

uri = URI.parse('http://server.com/path/to/resource')

# create a Net::HTTP object (the client with details of the server):
http_client = Net::HTTP.new(uri.host, uri.port)

# create a POST-object for the request:
your_post = Net::HTTP::Post.new(uri.path)

# the content (body) of your post-request:
your_post.body = 'your content'

# the headers for your post-request (you have to analyze before,
# which headers are mandatory for your request); for example:
your_post['Content-Type'] = 'put here the content-type'
your_post['Content-Length'] = your_post.body.size.to_s
# ...
# for an XMLHttpRequest you need (for example?) such header:
your_post['X-Requested-With'] = 'XMLHttpRequest'

# send the request to the server:
response = http_client.request(your_post)

# the body of the response:
puts response.body

Answer 3

XMLHTTPRequest是一个浏览器概念，但既然您问的是Ruby，那么我假设您想要做的就是从ruby脚本中模拟这样的请求？为此，有一个名为HTTParty的gem，它非常容易使用。

下面是一个简单的示例(假设您有gem -使用gem install httparty安装它)：

require 'httparty'
response = HTTParty.get('http://twitter.com/statuses/public_timeline.json')
puts response.body, response.code, response.message, response.headers.inspect