Python OpenWRT crontab

Question

我正在尝试在OpenWrt机器上运行python脚本：

#!/root/system/usr/bin/python
import subprocess

p = subprocess.Popen([r"snmpget","-v","1","-c","public","-Oqv","-Ln", "192.168.1.1","1.3.6.1.2.1.2.2.1.10.7"], stdout=subprocess.PIPE).communicate()[0]
data = [r"curl","-d","iface_id=1&content="+ str(p).rstrip() ,"http://192.168.1.5:8080/stat/add_istat/"]
a = subprocess.Popen(data, stdout=subprocess.PIPE).communicate()[0]

它通过snmp获取数据，然后通过curl将数据发送到本地服务器。它在shell中工作正常：

root@OpenWrt:~/python# ./w.py 
  % Total    % Received % Xferd  Average Speed   Time    Time     Time  Current
                                 Dload  Upload   Total   Spent    Left  Speed
  0    34    0     6    0    28     31    146 --:--:-- --:--:-- --:--:--     0

我可以在DB中看到数据。但是来自cron：

0-55/5 * * * * /root/python/w.py

我在logread中看到：

Dec 20 23:30:01 OpenWrt cron.err crond[1039]: USER root pid 16141 cmd /root/python/w.py

但在DB中没有数据:(在httpd access.log中也没有数据:(为什么？

Answer 1

是否snmpget或curl不在cron的路径中？

Answer 2

我用python urllib请求替换了curl，现在它可以工作了！:)

url = 'http://192.168.1.5:8080/stat/add_istat/"' # write ur URL here

values = {'iface_id' : '1', #write ur specific key/value pair
          'content' : str(p).rstrip(),
         }
try:
   data = urllib.urlencode(values)
   req = urllib2.Request(url, data)
   response = urllib2.urlopen(req)
   the_page = response.read()
   print the_page
except Exception, detail:
   print "Err ", detail