zend_mail中的返回路径问题

Question

你能告诉我为什么我设置returnPath使用zend_mail接收的电子邮件必须返回路径标题(我在gmail中查看它们)使用smtp传输：

Return-Path: <bounce@domain.com> //I think this is added by server
.....
Return-Path: bounce@domain.com //I think this is cause by returnPath

$mailer->setReturnPath('bounce@domain.com');

$emailConfig = $this->getOption('email');                                   
$transport = new Zend_Mail_Transport_Smtp($emailConfig['server'], $emailConfig);
Zend_Mail::setDefaultTransport($transport);

如果我没有设置returnPath服务器，添加returnPath与我在header中设置的相同。这是Zend_Mail中的一个bug还是什么？我的理解是，服务器将添加与在MAIL_FROM中使用的相同的返回路径报头，setReturnPath不应该手动添加报头，而是只保存它以供MAIL_FROM使用？It在Zend_Mail_Transport_Smtp更改代码注释行中：

/**
 * Sets the Return-Path header of the message
 *
 * @param  string    $email
 * @return Zend_Mail Provides fluent interface
 * @throws Zend_Mail_Exception if set multiple times
 */
public function setReturnPath($email)
{
    if ($this->_returnPath === null) {
        $email = $this->_filterEmail($email);
        $this->_returnPath = $email;

        //This line presents in Zend_Framework
        //I comment this like I get only one return-path the same as
        //set using setReturnPath method of Zend_Mail
        //$this->_storeHeader('Return-Path', $email, false);
    } else {
        /**
         * @see Zend_Mail_Exception
         */
        require_once 'Zend/Mail/Exception.php';
        throw new Zend_Mail_Exception('Return-Path Header set twice');
    }
    return $this;
}   

Answer 1

在Zend中，您可以通过显式选择传输将必要的附加参数传递给sendmail：

$tr = new Zend_Mail_Transport_Sendmail('-fmail@example.com');
 $_mail = new Zend_Mail();
 $_mail->setDefaultTransport($tr);

Answer 2

试试这个：

$mail->addHeader('Return-path', 'email@address.com');