在Symfony 2中创建ViewHelper

Question

How to create a ViewHelper in Symfony 2.我阅读了整个文档，但它没有描述任何类似的术语。它只有自动加载和服务。http://symfony.com/doc/current/cookbook/index.html

Answer 1

您只需创建一个实现帮助器函数的类并扩展

Symfony\Component\Templating\Helper\Helper

如下所示：

namespace Acme\Foo\Helper;


use Symfony\Component\Templating\Helper\Helper;

class MyViewHelper extends Helper {

    public function helpMe() {
       // do something
       return $value;
    }

   /**
    * @inheritdoc
    */
    public function getName() {
         return "anyCanonicalServiceName";
    }
}

然后你必须把你的帮助器作为一个带有特殊标签的服务来推广，例如

Resources/config/services.yml


services:
        your_service_name:
        class: Acme\Foo\Helper\MyViewHelper
        # the tag alias "myViewHelper" is later used in the view to access your service
        tags:
            - { name: templating.helper, alias: myViewHelper }

现在您可以在如下所示的视图中访问辅助对象：

echo $view['myViewHelper']->helpMe();