假设我想用下面的签名模拟一个方法:
public A foo(A a)我希望foo以某种方式被嘲笑,即它返回它接收到的内容(即相同的实例a)
我尝试了以下几种方法,但都没有成功:
Capture<A> capture = new Capture();
expect(myclass.foo(capture)).andReturn(capture.getValue());这不起作用,因为调用getValue()时捕获仍然为空。
有什么想法吗?
谢谢
发布于 2010-08-17 20:10:37
public class A {
public <A> A foo(A a) {
return null;
}
public static void main(String[] args) throws Exception {
A mock = createNiceMock(A.class);
expect(mock.foo(anyObject())).andAnswer(new IAnswer<Object>() {
@Override
public Object answer() throws Throwable {
return EasyMock.getCurrentArguments()[0];
}
}).anyTimes();
replay(mock);
System.out.println(mock.foo("1"));
System.out.println(mock.foo(2L));
}
}打印输出:
1
2https://stackoverflow.com/questions/3497261
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