是否可以按层次结构id对sql数据进行层次排序,然后对每个级别按字母顺序排序?
假设我们有一个Employees表,它根据Employees ID列出组织层次结构
您有Bob (5),Phil (17)和Charlie(28)向他汇报工作,Josie (6)让Tyler (15)和Mike (56)向她汇报工作。
如果您按HierarchyID对其进行排序,它将如下所示:
Bob (/5/)
--菲尔(/5/17/)
--查利(/5/28/)
乔西(/6/)
--泰勒(/6/15/)
--Mike (/6/56/)
但是让它看起来像这样更有意义
鲍勃
--查利
--菲尔
乔西
--迈克
--泰勒
这有可能在不让它变得太复杂的情况下实现吗?
发布于 2012-01-18 12:28:22
--这行得通吗?这张图片取自Sorting tree with other column in SQL Server 2008
DECLARE @table TABLE (id INT NOT NULL PRIMARY KEY, name NVARCHAR(4000) NOT NULL, path HIERARCHYID)
INSERT
INTO @table
VALUES
(1, 'People', '/'),
(2, 'Girls', '/1/'),
(3, 'Boys', '/2/'),
(4, 'Zoey', '/1/1/'),
(5, 'Kate', '/1/2/'),
(6, 'Monica', '/1/3/'),
(7, 'Mark', '/2/1/'),
(8, 'David', '/2/2/')
;WITH q AS
(
SELECT *, HIERARCHYID::Parse('/') AS newpath
FROM @table
WHERE path = HIERARCHYID::GetRoot()
UNION ALL
SELECT t.*, HIERARCHYID::Parse(q.newpath.ToString() + CAST(ROW_NUMBER() OVER (ORDER BY t.name) AS NVARCHAR(MAX)) + '/')
FROM q
JOIN @table t
ON t.path.IsDescendantOf(q.path) = 1
AND t.path.GetLevel() = q.path.GetLevel() + 1
)
SELECT replicate(convert(nvarchar, '-'), q.path.GetLevel()) + q.name /*+ '(' + q.newpath.ToString() + ')'*/
FROM q
ORDER BY
newpath发布于 2012-10-18 17:41:39
这就是我找到的解决方案
declare @oldId hierarchyid, @newId hierarchyid, @parent hierarchyid
select @oldId = id_node, @parent = id_node.GetAncestor(1)
from gbs.T_Hierarchy_Activities ha
where ID = @ID_Object
select @newId = @oldId.GetReparentedValue(@oldId, ID_Node) from (
select row_number() over(order by id_node) rn, id_node
from gbs.T_Hierarchy_Activities ha
cross join (select * from common.FX_Permissions() where ID_Feature = 10) p
where ID_Node.IsDescendantOf(@oldId.GetAncestor(1)) = 1
and ID_Level = @oldId.GetLevel()
and ha.ID_Office = p.ID_Office
) a
where rn = @NewPosition
update gbs.T_Hierarchy_Activities
set ID_Node = case when ID_Node = @oldId then @newId else @oldId end
where ID_Node in (@oldId, @newId)发布于 2012-01-18 01:51:47
除非我误解了什么,否则您可以在ORDER BY子句中添加一个辅助排序字段。例如:
SELECT * FROM Employees ORDER BY HierarchyID, Namehttps://stackoverflow.com/questions/8899230
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