如何在while循环中扫描多个输入？

Question

while((player1chip==-1)||(player2chip==-1)||(player3chip==-1)){                                                              
    player1chip=-1; player2chip=-1; player3chip=-1;                                                       
    printf("How many chips would you like to play with (3-10):\n");
    scanf("%d%d%d", &player1chip, &player2chip, &player3chip);
    getchar();
}

我想一次得到3个值，但循环似乎已经运行了3次…我该怎么做呢？

Answer 1

int p1chip=-1, p2chip=-1, p3chip=-1;
do {
  printf("How many chips would you like to play with (3-10)?\n");
  scanf("%d%d%d", &p1chip, &p2chip, &p3chip);
} while ((p1chip == -1) || (p2chip == -1) || (p3chip == -1))

试试看。

Answer 2

scanf()语句对于您正在尝试做的事情有点奇怪，因为您说您需要使用"%d%d%d“没有分隔的三个数字。如果while循环的目的是填充playerchip变量，则应该对它们使用一个数组并迭代该数组，如下所示：

playerchip[3];   
for(int i=0; i<3; i++) {
    printf("How many chips would player %d like to play with (3-10)?:\n", i);
    scanf("%d", &playerchip[i]);
}

如果您保留您的命名方案，则不能使用循环轻松地填充变量。不过，为了回答您最初的问题，要一次获取多个数字，您需要在scanf()语句中使用一些分隔符：

scanf("%d %d %d", &a, &b, &c);

这样，每个人都知道一个数字何时结束，另一个何时开始。