我正在使用jQTouch框架为iPhone开发一个web应用程序。我发现了一个类似于我想要如何设置我的登录页面的示例:
http://www.golen.net/blog/2010/05/29/jqtouch-ajax-php-login-form/
并下载了示例php文件:http://www.golen.net/blog/wp-content/uploads/2010/05/jqtouch.zip
在本博客随附的视频3中,它显示登录表单不会出现,除非您单击登录链接。然而,我已经下载了这些文件并将它们上传到我的两台服务器上,无论我是否已经登录,登录表单总是会出现。据我所知,可下载的php文件与视频中的内容相同,但我无法阻止登录表单始终显示。
任何人都有任何想法。下面是包含登录表单的index.php页面:
<?php$loggedIn =(isset($_COOKIE‘$loggedIn’) && $_COOKIE‘$loggedIn’== 'true')?true:false;?>
<title>jQTouch β</title>
<style type="text/css" media="screen">@import "jqtouch/jqtouch.css";</style>
<style type="text/css" media="screen">@import "themes/jqt/theme.css";</style>
<script src="jqtouch/jquery-1.4.2.min.js" type="text/javascript" charset="utf-8"></script>
<script src="jqtouch/jqtouch.js" type="application/x-javascript" charset="utf-8"></script>
<script type="text/javascript" charset="utf-8">
var jQT = new $.jQTouch({
icon: 'jqtouch.png',
addGlossToIcon: false,
startupScreen: 'jqt_startup.png',
statusBar: 'black',
preloadImages: [
'themes/jqt/img/back_button.png',
'themes/jqt/img/back_button_clicked.png',
'themes/jqt/img/button_clicked.png',
'themes/jqt/img/grayButton.png',
'themes/jqt/img/whiteButton.png',
'themes/jqt/img/loading.gif'
]
});
// Some sample Javascript functions:
$(function(){
});
</script>
</head>
<body>
<div id="jqt">
<div id="home">
<div class="toolbar">
<h1>Welcome</h1>
<a class="back" href="#home">Home</a>
</div>
<?php if (!$loggedIn) {?>
<ul class="rounded">
<li class="forward"><a href="#login">Log In</a></li>
</ul>
<?php } else { ?>
<ul class="rounded">
<li class="forward"><a href="doLogoff.php" rel="external">Log off</a></li>
</ul>
<?php } ?>
</div>
<form id="login" action="doLogin.php" method="POST" class="form">
<div class="toolbar">
<h1>Login</h1>
<a class="back" href="#">Back</a>
</div>
<ul class="rounded">
<li><input type="text" name="username" value="" placeholder="Username" /></li>
<li><input type="password" name="password" value="" placeholder="Password" /></li>
</ul>
<a style="margin:0 10px;color:rgba(0,0,0,.9)" href="#" class="submit whiteButton">Submit</a>
</form>
</div>
</body>
发布于 2011-02-03 06:50:51
你只需要稍微修改一下代码...删除jqt div,然后放入一个div id‘id’login...,如下所示:
<body>
<div id="home">
<div class="toolbar">
<h1>Welcome</h1>
<a class="back" href="#home">Home</a>
</div>
<?php if (!$loggedIn) {?>
<ul class="rounded">
<li class="forward"><a href="#login">Log In</a></li>
</ul>
<?php } else { ?>
<ul class="rounded">
<li class="forward"><a href="doLogoff.php" rel="external">Log off</a></li>
</ul>
<?php } ?>
</div>
<div id="login">
<form id="login" action="doLogin.php" method="POST" class="form">
<div class="toolbar">
<h1>Login</h1>
<a class="back" href="#">Back</a>
</div>
<ul class="rounded">
<li><input type="text" name="username" value="" placeholder="Username" /></li>
<li><input type="password" name="password" value="" placeholder="Password" /></li>
</ul>
<a style="margin:0 10px;color:rgba(0,0,0,.9)" href="#" class="submit whiteButton">Submit</a>
</form>
</div>
</body>希望这对你有帮助:-)
https://stackoverflow.com/questions/3572270
复制相似问题