Matplotlib表格格式-更改行标签单元格的宽度

Question

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我对这个表有一个明显的问题，因为行标签在图的外部，我不知道如何修复它。我知道我可以进入儿童艺术家，并在那里改变高度和宽度等设置，但我已经尝试过了，它不起作用，所以也许你现在可以帮助我。

这是我用来做这个的代码，希望它不会太难读……：

ind1=np.arange(5)


figure()
axes([0.2, 0.45, 0.7, 0.45])

## define different bars
l1=bar((ind1-0.45),mean_morphing_cc[0:5],width=0.2,bottom=0,color='darkblue',yerr=[min_dif_morphing_cc[0:5],max_dif_morphing_cc[0:5]],error_kw=dict(elinewidth=2, ecolor='darkkhaki'))

l2=bar((ind1-0.25),mean_persistence_cc[0:5],width=0.2,bottom=0,color='darkred',yerr=[min_dif_persistence_cc[0:5],max_dif_persistence_cc[0:5]],error_kw=dict(elinewidth=2, ecolor='darkkhaki'))

l3=bar((ind1+0.05),mean_m_vs_p_cc[0:5],width=0.2,bottom=0,color='purple',yerr=[min_dif_m_vs_p_cc[0:5],max_dif_m_vs_p_cc[0:5]],error_kw=dict(elinewidth=2, ecolor='darkkhaki'))

## print grid and a horizontal line at "0"
grid(True, linestyle='-', which='major', color='lightgrey',alpha=0.5)

hlines(0, -0.5,(max(ind1)+0.5), colors='k', linestyles='solid')


ylabel('mean((cloud cover_forecast/cloud cover_observation)-1),\n mean("morphing" - "persistence")',horizontalalignment='right',multialignment='center',size='xx-small')

xlim(-0.5,(max(ind1)+0.5))

xticks(ind1,[])

## print a legend
legend((l1[0],l2[0],l3[0]),('mean morphing cloud cover','mean persistence cloud cover','mean morphing vs persistence error'),'lower center',ncol=2,bbox_to_anchor=(0.5,-0.92),borderpad=0.2,labelspacing=0.2,handlelength=1,handletextpad=0.2)

leg = plt.gca().get_legend()

ltext  = leg.get_texts()  # all the text.Text instance in the legend

llines = leg.get_lines()  # all the lines.Line2D instance in the legend

frame  = leg.get_frame()  # the patch.Rectangle instance surrounding the legend

frame.set_facecolor('0.90')      # set the frame face color to light gray

plt.setp(ltext, fontsize='x-small')    # the legend text fontsize

## print the title
title('cloud cover over- or underestimation\n morphing forecast compared to persistence',size='small')

## print the table
the_table=plt.table(cellText=[[str(i)[:4] for i in mean_morphing_cc[0:5]],max_morphing_cc[0:5],min_morphing_cc[0:5],mean_persistence_cc[0:5],max_persistence_cc[0:5],min_persistence_cc[0:5],mean_m_vs_p_cc[0:5],max_m_vs_p_cc[0:5],min_m_vs_p_cc[0:5]],
                    rowLabels=['morphing: mean','morphing: max','morphing: min','persistence: mean','persistence: max','persistence: min','morph vs per: mean','morph vs per: max','morph vs per: min'],
                    rowColours=['darkblue','darkblue','darkblue','darkred','darkred','darkred','purple','purple','purple'],colLabels=['t+1','t+2','t+3','t+4','t+5'],loc='bottom')

## change cell properties
table_props=the_table.properties()
table_cells=table_props['child_artists']
for cell in table_cells:
    cell.set_width(0.2)
    cell.set_height(0.065)
    cell.set_fontsize(12)

show()

Answer 1

我还没有找到这个问题的完美答案，但我已经找到了一个对我自己的目的有用的解决方案。

同时调整colWidth和表的宽度可以缩小行标签列的宽度。在source code中，他们实际上使用了一个变量rowLabelWidth，但是他们不让用户设置它。不管怎样，首先我要重写你的现有代码，这样你就可以看到在哪里做了修改。这是一个可变格式的原件：

## setting properties to variables to make table function easier to read
data = [[str(i)[:4] for i in mean_morphing_cc[0:5]],max_morphing_cc[0:5],min_morphing_cc[0:5],mean_persistence_cc[0:5],max_persistence_cc[0:5],min_persistence_cc[0:5],mean_m_vs_p_cc[0:5],max_m_vs_p_cc[0:5],min_m_vs_p_cc[0:5]]
rowLabels = ['morphing: mean','morphing: max','morphing: min','persistence: mean','persistence: max','persistence: min','morph vs per: mean','morph vs per: max','morph vs per: min']
rowColours = ['darkblue','darkblue','darkblue','darkred','darkred','darkred','purple','purple','purple']
colLabels = ['t+1','t+2','t+3','t+4','t+5']
loc = 'bottom'

## without changing anything, this is what your table function would look like
the_table=plt.table(cellText = data,
                rowLabels = rowLabels, rowColours = rowColours,
                colLabels = colLabels, loc = loc)

下面是rowLabelWidth源代码中的内容，我们将使用它们来帮助确定要将width和colWidth设置为什么。

# Do row labels
if rowLabels is not None:
    for row in xrange(rows):
        table.add_cell(row + offset, -1,
                       width=rowLabelWidth or 1e-15, height=height,
                       text=rowLabels[row], facecolor=rowColours[row],
                       loc=rowLoc)
    if rowLabelWidth == 0:
        table.auto_set_column_width(-1)

您似乎已经将图表的宽度设置为轴(0.2，0.45，0.7，0.45)到0.7，因此我们将其设置为变量tb_width

tb_width = 0.7

rowLabelWidth会自动调整大小，这对我们并没有真正的帮助。但是，如果您尝试使用colWidths的以下三个选项，您就可以开始弄清楚如何让它以您想要的方式工作。在bbox属性中添加，以指定表的具体位置。需要注意的重要一点是，rowLabelWidth似乎并未包含在整个表格宽度中。

## standard - essentially what happens when you don't specify colWidths. Takes the table width, divides it by the number of columns, giving each column an equal width.
colWidths = [tb_width/n_cols] * n_cols
## rowLabels stick out on the left

## similar to the above, but the '+1' attempts to account for the fact that another column's width, rowLabels, should fit inside the overall table width
colWidths=[( tb_width / (n_cols + 1) )] * n_cols  

## set your own width. this will start messing with the width of the rowLabelsWidth as now the colWidths aren't perfectly proportioned within the table width
tb_colWidth = 0.08
colWidths = [tb_colWidth] * n_cols

要确保rowLabels适合图表的正下方而不突出于左侧，请使用bbox坐标。使用表格的左下角作为参考点，定位表格: bbox=x_coordinate、y_coordinate、width、height。如果x_coordinate被设置为考虑您的tb_colWidth，那么它将使表移动所需的量，以使rowLabels-column的最左侧直接位于上面图表的左下角。

bbox = [tb_colWidth, y_coordinate, tb_width, tb_height]

如果现在这会导致最右侧的列从图表下伸出，则将宽度缩小一列的大小：

bbox = [tb_colWidth, y_coordinate, tb_width - tb_colWidth, tb_height]

现在把它们放在一起：

the_table=plt.table(cellText = data,
            rowLabels = rowLabels, rowColours = rowColours,
            colLabels = colLabels, loc = 'bottom',
            colWidths = colWidths, bbox = bbox)

您不应该执行调整单元格宽度的最终表单元格循环，而是可以使用上面的工具进行控制。

Answer 2

我遇到了这个问题，我通过将行标签的对齐方式从“左”改为“右”，部分修复了这个问题。

cellDict = the_table.get_celld()
for x in range(1, len(row_labels)+1):
    cellDict[(x,-1)]._loc = 'right'

get_celld()返回单元格的字典，cellDict(x，-1)选择x行和-1列中的单元格，即行标签列。

这不会更改行标签列的宽度，因此标签左侧可能仍留有空格。我的页面显示在屏幕左侧，但至少我现在可以看到行标签中的所有文本了。