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社区首页 >问答首页 >如果用户使用键盘输入时间,则TimePicker仅显示分钟并设置最大分钟数

如果用户使用键盘输入时间,则TimePicker仅显示分钟并设置最大分钟数
EN

Stack Overflow用户
提问于 2011-01-21 17:42:17
回答 2查看 7K关注 0票数 0

这就是我的时间选择器现在的样子。我希望它只显示分钟和分钟只到最多30分钟。它工作得很好,但当你用键盘输入时间时,它会将时间设置为0,但我希望它设置为最大值。那么,如果用户输入50,它应该转到30,我该怎么做呢?我如何隐藏时间选择器的小时,因为这里不需要它。

代码语言:javascript
复制
protected void onCreate(Bundle savedInstanceState) {
    System.out.println("Powernap");
    super.onCreate(savedInstanceState);
    setContentView(R.layout.powernap);
    TimePicker pn = (TimePicker) findViewById(R.id.tp_powernap);

    pn.setOnTimeChangedListener(StartTimeChangedListener);
    pn.setIs24HourView(true);
}

    private TimePicker.OnTimeChangedListener StartTimeChangedListener =
        new TimePicker.OnTimeChangedListener() {

        public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {
            updateDisplay(view, hourOfDay, minute);          
        }
    };

    private TimePicker.OnTimeChangedListener NullTimeChangedListener =
        new TimePicker.OnTimeChangedListener() {

        public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {

        }
    };

    private void updateDisplay(TimePicker timePicker, int hourOfDay, int minute) { 

        // do calculation of next time 
        int nextMinute = 0;
        int nextHour = 0;
        if (minute > 30){
            System.out.println("Minute+30");
            nextMinute = 30;
            // set minute
            timePicker.setCurrentMinute(nextMinute);
        }
        else {          
            System.out.println("minute 0");
            nextMinute = 0;
        }
        if (hourOfDay != 0){
            System.out.println("hour>0");
            nextHour = 24;
        }

        // remove ontimechangedlistener to prevent stackoverflow/infinite loop
        timePicker.setOnTimeChangedListener(NullTimeChangedListener);

        // set minute
        timePicker.setCurrentMinute(timePicker.getCurrentMinute()+nextMinute);

        //set hour
        timePicker.setCurrentHour(nextHour);

        // hook up ontimechangedlistener again
        timePicker.setOnTimeChangedListener(StartTimeChangedListener);

    }
EN

回答 2

Stack Overflow用户

发布于 2011-02-01 15:37:13

这就是我如何用最大和最小的步骤和5分钟的步骤来做这部分,有关于stackoverflow的示例,但在他们的方法中,你不能同时使用向上和向下按钮,在我的方法中它是有效的:

代码语言:javascript
复制
public class Powernap extends Activity {



/** Called when the activity is first created. */
@Override
protected void onCreate(Bundle savedInstanceState) {
    System.out.println("Powernap");
    super.onCreate(savedInstanceState);
    setContentView(R.layout.powernap);
    TimePicker pn = (TimePicker) findViewById(R.id.tp_powernap);
    pn.setCurrentMinute(5);
    System.out.println("timepicker erstellt");
    pn.setDescendantFocusability(TimePicker.FOCUS_BLOCK_DESCENDANTS);
    System.out.println("Tastatur geblockt");
    pn.setOnTimeChangedListener(StartTimeChangedListener);
    System.out.println("starttimechangedlistener");
    pn.setIs24HourView(true);
}


    private TimePicker.OnTimeChangedListener StartTimeChangedListener =
        new TimePicker.OnTimeChangedListener() {

        public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {
            updateDisplay(view, hourOfDay, minute);          
        }
    };

    private TimePicker.OnTimeChangedListener NullTimeChangedListener =
        new TimePicker.OnTimeChangedListener() {

        public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {

        }
    };

    private void updateDisplay(TimePicker timePicker, int hourOfDay, int minute) { 

        // do calculation of next time 
        int nextMinute = 0;
        int nextHour = 0;
        if (minute >= 30 && minute <= 59){
            System.out.println("Minute+30");
            nextMinute = 30;
        }
        else if(minute == 26){
            System.out.println("Minute auf 30");
            nextMinute = 30;
        }
        else if(minute == 25 || minute == 21 || minute == 29){
            System.out.println("Minute auf 25");
            nextMinute = 25;
        }
        else if(minute == 20 || minute == 16 || minute == 24){
            System.out.println("Minute auf 20");
            nextMinute = 20;
        }
        else if(minute == 15 || minute == 11 || minute == 19){
            System.out.println("Minute auf 15");
            nextMinute = 15;
        }
        else if(minute == 10 || minute == 6 || minute == 14){
            System.out.println("Minute auf 10");
            nextMinute = 10;
        }
        else if(minute == 5 || minute == 1 || minute == 9 || minute < 5){
            System.out.println("Minute auf 5");
            nextMinute = 5;
        }





        if (hourOfDay != 0){
            System.out.println("hour>0");
            nextHour = 24;
        }

        // remove ontimechangedlistener to prevent stackoverflow/infinite loop
        timePicker.setOnTimeChangedListener(NullTimeChangedListener);

        // set minute
        timePicker.setCurrentMinute(nextMinute);

        //set hour
        timePicker.setCurrentHour(nextHour);

        // hook up ontimechangedlistener again
        timePicker.setOnTimeChangedListener(StartTimeChangedListener);

    }
票数 4
EN

Stack Overflow用户

发布于 2011-01-28 01:02:29

您需要编写自己的小部件。TimePicker小部件或TimePickerDialog不支持您想要的内容。

票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/4757317

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