我正在用MySQL5.0构建一个查询来计算学生的学期成绩。初始表(studentItemGrades)包含作业列表等,这些作业将用于计算期末成绩。每个作业都有PossibleScore、等级和权重。计算应该对所有类似权重的项目进行分组,并根据作业到期的日期范围提供总和(成绩)/SUM(POSSIBLESCORE)。我遇到的问题是所有个人加权分数的最终总和。例如,结果当前生成以下内容:
CourseScheduleID sDBID AssignedDate DueDate Weight WeightedGrade
1 519 2010-08-26 2010-08-30 10 0.0783333333333333
1 519 2010-09-01 2010-09-03 20 0.176
1 519 2010-09-01 2010-09-10 70 0.574从查询中:
SELECT CourseScheduleID, sDBID, AssignedDate, DueDate, Weight,
((SUM(Grade)/SUM(PossibleScore))*(Weight/100)) AS WeightedGrade
FROM studentItemGrades
WHERE DueDate>='2010-08-23'
AND DueDate<='2010-09-10'
AND CourseScheduleID=1
AND sDBID=519
AND Status>0
GROUP BY Weight问题:现在如何在WeighedGrade输出中对这三个结果求和?顺便说一句,这是一个更大的查询的一部分,用于计算特定校园中所有课程的所有分数。
提前感谢您的帮助。
发布于 2011-05-18 02:34:59
您可以使用子查询,如下所示:
SELECT SUM(WeightedGrade) FROM
(
SELECT CourseScheduleID, sDBID, AssignedDate, DueDate, Weight,
((SUM(Grade)/SUM(PossibleScore))*(Weight/100)) AS WeightedGrade
FROM studentItemGrades
WHERE DueDate>='2010-08-23'
AND DueDate<='2010-09-10'
AND CourseScheduleID=1
AND sDBID=519
AND Status>0
GROUP BY Weight
) t1发布于 2011-05-18 02:40:40
为了对这三个结果求和,您需要使用带有group by的另一个select重新查询此select的结果。这可以通过使用子查询使用单个sql语句来完成。
SELECT sq.CourseScheduleID, sq.sDBID, SUM(sq.WeightedGrade) as FinalGrade
FROM
(
SELECT CourseScheduleID, sDBID, AssignedDate, DueDate, Weight,
((SUM(Grade)/SUM (PossibleScore))*(Weight/100)) AS WeightedGrade
FROM studentItemGrades WHERE DueDate>='2010-08-23' AND DueDate<='2010-09-10'
AND CourseScheduleID=1 AND sDBID=519 AND Status>0 GROUP BY Weight
) AS sq
GROUP BY sq.CourseScheduleID, sq.sDBIDhttps://stackoverflow.com/questions/6035420
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