用于服务的KeyguardManager FLAG_DISMISS_KEYGUARD

Question

当屏幕打开时，我想检查电源按钮是否被激活，如果是，它将自动解除键盘保护并运行吐司。

当屏幕关闭时，键盘保护将重新启用。(代码在这里一直有效)

(但它会进入检测“电源”按钮被按下的循环中)。

情况应该是，当按下其他按钮(“电源”按钮除外)时，不应激活“解除键盘保护”。

非常感谢任何帮助来解决这个错误:)

另一个问题-如何在服务中使用FLAG_DISMISS_KEYGUARD？

public class myService extends Service{

@Override
public IBinder onBind(Intent arg0) {
    // TODO Auto-generated method stub
    return null;
}

@Override
public void onCreate() {
    super.onCreate();

}

@Override
public void onStart(Intent intent, int startId) {
    boolean screenOn = intent.getBooleanExtra("screen_state", false);
    boolean pressed = false;       
    Vibrator myVib;

    //screen is turned on
    if (!screenOn) 
    {
        pressed = onKeyDown(26, null);

        //if it turned on by power button. bug = always go into this loop
        if(pressed)
        {
            Context context = getApplicationContext();
            CharSequence text = "Service started. power button pressed";
            int duration = Toast.LENGTH_SHORT;

            Toast toast = Toast.makeText(context, text, duration);
            toast.show();               

            //dimiss keyguard
            KeyguardManager keyguardManager = (KeyguardManager)getSystemService(Activity.KEYGUARD_SERVICE);
            KeyguardLock lock = keyguardManager.newKeyguardLock(KEYGUARD_SERVICE);
            lock.disableKeyguard();


            Context context2 = getApplicationContext();
            CharSequence text2 = "SCREEN ON";
            int duration2 = Toast.LENGTH_SHORT;

            Toast toast2 = Toast.makeText(context2, text2, duration2);
            toast2.show();

        }           
        else
        {
            Context context = getApplicationContext();
            CharSequence text = "Service started. NOT power button pressed";
            int duration = Toast.LENGTH_SHORT;

            Toast toast = Toast.makeText(context, text, duration);
            toast.show();
        }

    }

    //screen is turned off
    else {
        myVib = (Vibrator) this.getSystemService(VIBRATOR_SERVICE);
        myVib.vibrate(500);

        KeyguardManager keyguardManager = (KeyguardManager)getSystemService(Activity.KEYGUARD_SERVICE);
        KeyguardLock lock = keyguardManager.newKeyguardLock(KEYGUARD_SERVICE);
        lock.reenableKeyguard();

    }
}

 public boolean onKeyDown(int keyCode, KeyEvent event) {
     if(keyCode == KeyEvent.KEYCODE_POWER)
         return true;
     else
        return false;
 }
}//end of myService class

Answer 1

好吧，这并不像看起来那么简单，服务不能实际拥有当前正在运行的活动，但您需要一个活动来获取对窗口的引用

​

所以你可以用几种不同的方法来实现。

Turning off the screen from a service

在此问题的答案中，创建了一个虚拟活动(未膨胀的活动)，并用于获取窗口(可以工作，但不确定未膨胀的活动是否会导致泄漏或其他问题。此外，它看起来有点像一个肮脏的黑客)

或者..。

CommonWares方式

how can i get the current foreground activity from a service

当您的服务向将要执行此操作的活动广播意图时，您可以在触发的回调中处理实际的窗口操作。(更好的设计，但更具原始性的返工) Example

​

一旦你决定了你想怎么做(我推荐#2)，下面的方法应该是有效的，但请注意，我还没有测试过它。

//Get the window from the context
WindowManager wm = Context.getSystemService(Context.WINDOW_SERVICE);

//Unlock
//http://developer.android.com/reference/android/app/Activity.html#getWindow()
Window window = getWindow();  
window.addFlags(wm.LayoutParams.FLAG_DISMISS_KEYGUARD);  

//Lock device
DevicePolicyManager mDPM;
mDPM = (DevicePolicyManager)getSystemService(Context.DEVICE_POLICY_SERVICE);