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Leetcode 165. Compare Version Numbers

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Tyan
发布于 2021-05-06 16:47:52
发布于 2021-05-06 16:47:52
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文章被收录于专栏:SnailTyanSnailTyan

1. Description

2. Solution

  • Version 1
代码语言:javascript
复制
class Solution:
    def compareVersion(self, version1: str, version2: str) -> int:
        v1 = version1.split('.')
        v2 = version2.split('.')
        
        length1 = len(v1)
        length2 = len(v2)
            
        for i in range(min(length1, length2)):
            if int(v1[i]) < int(v2[i]):
                return -1
            elif int(v1[i]) > int(v2[i]):
                return 1
        if length1 > length2:
            for i in range(length2, length1):
                if int(v1[i]) > 0:
                    return 1
        else:
            for i in range(length1, length2):
                if int(v2[i]) > 0:
                    return -1
        return 0

Reference

  1. https://leetcode.com/problems/compare-version-numbers/
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原始发表:2021/04/30 ,如有侵权请联系 cloudcommunity@tencent.com 删除
目录
  • 2. Solution
  • Reference
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